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The conducting rod AB of length l = 1 m is moving at a velocity v =4 m/s making an angle 30⁰ with its length. A uniform magnetic field B=2T exists in a direction perpendicular to the plane to motion. Then

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$V_{A} - V_{B} = 8 V$

$V_{A} - V_{B} = 4 V$

$V_{B} - V_{A} = 8 V$

$V_{B} - V_{A} = 4 V$

answer is B.

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Detailed Solution

$V_{A} - V_{B} = B l [Vsin 30^{0}] = 4 V$

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