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Q.

The conducting shells A and B are arranged as shown below. If charge on the shell B is ‘q’ then electric flux linked with the spherical Gaussian surface S is

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a

$- \frac{q}{2 ε_{0}}$

b

$\frac{q}{ε_{0}}$

c

$- \frac{q}{ε_{0}}$

d

$\frac{q}{2 ε_{0}}$

answer is B.

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Detailed Solution

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Question Image

$V_{A} = \frac{1}{4 π ε_{0}} (\frac{q_{A}}{r} + \frac{q}{2 r}) = 0$

$q_{A} = \frac{- q}{2} \Rightarrow ϕ = \frac{q_{A}}{ε_{0}} = \frac{- q}{2 ε_{0}}$

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