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The conductivity of 0.1 M NaOH is 0.022 S cm1. When equal volume of 0.1 M HCl is added to this solution, the conduction of the solution becomes 0.00632 S cm1. The molar conductivity of sodium chloride in the resultant solution is

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a
126.4 S cm2 mol1
b
63.2 S cm2mol1
c
189.6 S cm2mol1
d
112.2 S cm2mol1

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detailed solution

Correct option is A

The concentration of NaCl in the resultant solution will be 0.05 M. Hence,

Λ=κc=0.00632Scm10.05moldm3=0.1264Scm1mol1dm3=0.1264Scm1mol1(10cm)3=126.4Scm2mol1

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