The conductivity of saturated solution of AgCl is found to $1.86\times {10}^{-6}{\mathrm{ohm}}^{-1}{\mathrm{cm}}^{-1}$ and that of water is $6\times {10}^{-8}{\mathrm{ohm}}^{-1}{\mathrm{cm}}^{-1}\text{. If }{\mathrm{\lambda }}^0\mathrm{AgCl}\text{ is }138$ ${\mathrm{ohm}}^{-1}{\mathrm{cm}}^2{\mathrm{eq}}^{-1}$ the solubility product of AgCl is