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The constant $α$ of a transistor is 0.9. What would be the change in the collector current corresponding to a change of 4 mA in the base current in a common emitter arrangement ?

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30mA

63mA

36 mA

3.6 mA

answer is C.

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Detailed Solution

$\begin{array}{l} β = \frac{α}{1 - α} But β = {(\frac{{δI}_{C}}{{δI}_{B}})}_{V_{CE}} \\ \Rightarrow {δI}_{C} = β . {δI}_{B} = 9 \times 4 mA \end{array}$

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