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Q.

The conversion of $A \to B$ follows second-order kinetics. Doubling the concentration of A will increase the rate of formation of B by a factor

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a

1/4

b

2

c

1/2

d

4

answer is D.

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Detailed Solution

$r = k {(A)}^{2}$ , when concentration is doubled

$r = k {(2 A)}^{2} = k 4 {(A)}^{2}$ the rate becomes 4 times.

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