The coordinates of centre of mass of a uniform  flag shaped lamina (thin flat plate) of mass 4 kg . (The  coordinates of the same are shown in figure ) are :

 

The provided lamina can be split into two pieces as displayed.

These parts' mass and location of their centre of mass are determined by,

${\mathrm{m}}_1=1, {\mathrm{C}}_1=(1.5 , 2.5)$

${\mathrm{m}}_2=3, {\mathrm{C}}_2=(0.5,1.5)$

${\mathrm{x}}_{\mathrm{cm}}=\frac{{\mathrm{m}}_1{\mathrm{x}}_1+{\mathrm{m}}_1{\mathrm{x}}_2}{{\mathrm{m}}_1+{\mathrm{m}}_2}=\frac{1.5+1.5}{4}=0.75$

${\mathrm{y}}_{\mathrm{cm}}=\frac{{\mathrm{m}}_1{\mathrm{y}}_1+{\mathrm{m}}_1{\mathrm{y}}_2}{{\mathrm{m}}_1+{\mathrm{m}}_2}=\frac{2.5+4.5}{4}=1.75$

Hence the correct answer is (0.75m,1.75m).