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Q.

The coordinates of point P are (a,b) where a is root of the equation x2+x42=0 and b is integral root of the equation x2+ax+(a237)=0 . The coordinates P can be

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a

(7,4)

b

(6,3)

c

(6,4)

d

(7,3)

answer is C.

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Detailed Solution

x2+x42=0x=7,6

If a=7,x27x+12=0x=4,3

P=(7,4)(or)(7,3)

If a=6,x2+6x1=0,Δ=36+4=40>0  and not a perfect square

 Roots are irrational

'b'  does not exist in this case

P=(7,4)(or)(7,3)

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