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Q.

The coordination number of metal M in a complex having molecular formula MCl3.(H2O)4 is 6 and there is no molecule of water of crystallization in it. The volume of 0.1M AgNO3 solution needed to precipitate the free chloride ions in 200 mL of 0.01 M complex is

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a

40 mL

b

80 mL

c

60 mL

d

20 mL

answer is B.

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Detailed Solution

Metal coordination number M = 6
Number of Hydration Molecules = 0
As a result, the complex formula = MH2O4Cl2ClMH2O4Cl2Cl⟶ MH2O4Cl2NO3+AgCICl-+AgNO3⟶NO3-+AgCl
Let the volume of AgNO3 used equal V.
M1xC1 = M1xC2
0.1×V=200×0.01
V=20mL
 

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