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Q.

The correct arrangement of decreasing order of atomic radius among Na, K, Mg and Rb is

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a

Rb > Na > K > M

b

K > Rb > Na > Mg

c

Rb > K > Na > Mg

d

Mg > Rb > K > Na

answer is C.

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Detailed Solution

Na, K and Rb are of group I elements and size increase down
the group 1 elements ().

Na and Mg are of group 1 and 2 elements respectively but both belong to 3rd period. Along the period size decreases (), i.e. size of Na > Mg.

Hence the order of sizes is

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