The correct combination is i) CH3−CH=CH2⟶HBrCH3−CHBr−CH3− electrophililc additionii) C6H6→AlCl3CH3COClC6H5−C||O−CH3 electrophililc substitutioniii) C6H6→hvCl2C6H6Cl6 - free radical additioniv) CH3−CH=CH2→per oxideHBrCH3CH2CH2Br electrophilic addition

CH3−CH=CH2→per oxideHBrCH3CH2CH2Br is the free radical addition

The correct combination is i) CH3−CH=CH2⟶HBrCH3−CHBr−CH3− electrophililc additionii) C6H6→AlCl3CH3COClC6H5−C||O−CH3 electrophililc substitutioniii) C6H6→hvCl2C6H6Cl6 - free radical additioniv) CH3−CH=CH2→per oxideHBrCH3CH2CH2Br electrophilic addition

CH3−CH=CH2→per oxideHBrCH3CH2CH2Br is the free radical addition

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The correct combination is
i) ${CH}_{3} - CH = {CH}_{2} \overset{HBr}{⟶} {CH}_{3} - CHBr - {CH}_{3} -$ electrophililc addition
ii) $C_{6} H_{6} \to_{A l C l_{3}}^{C H_{3} C O C l} C_{6} H_{5} - \underset{\begin{array}{l} | | \\ O \end{array}}{C} - C H_{3}$ electrophililc substitution
iii) $C_{6} H_{6} \to_{h v}^{C l_{2}} C_{6} H_{6} C l_{6}$ - free radical addition
iv) $C H_{3} - C H = C H_{2} \to_{p e r o x i d e}^{H B r} C H_{3} C H_{2} C H_{2} B r$ electrophilic addition

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(i), (ii), (iii), and (iv)

Only ii & iii

Only i, ii & iii

Only ii & iv

answer is C.

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$C H_{3} - C H = C H_{2} \to_{p e r o x i d e}^{H B r} C H_{3} C H_{2} C H_{2} B r$ is the free radical addition

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The correct combination is i) CH3−CH=CH2⟶HBrCH3−CHBr−CH3− electrophililc additionii) C6H6→AlCl3CH3COClC6H5−C||O−CH3 electrophililc substitutioniii) C6H6→hvCl2C6H6Cl6 - free radical additioniv) CH3−CH=CH2→per oxideHBrCH3CH2CH2Br electrophilic addition

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