The correct decreasing order of basicity of hydrides of group-15 elements is

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${NH}_{3} > {PH}_{3} > {AsH}_{3} > {SbH}_{3}$

${AsH}_{3} > {SbH}_{3} > {NH}_{3} > {PH}_{3}$

${SbH}_{3} > {AsH}_{3} > {PH}_{3} > {NH}_{3}$

${PH}_{3} > {AsH}_{3} > {SbH}_{3} > {NH}_{3}$

answer is D.

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Detailed Solution

In general, the basicity of group 15 hydrides decreases on moving down the group from NH₃ to SbH₄. This is due to the increasing size of the central atom and the decreasing availability of lone pair for donation. Thus, the correct order of basicity of hydrides is

${NH}_{3} > {PH}_{3} > {AsH}_{3} > {SbH}_{3}$

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