The correct decreasing priority of ligands $-{\mathrm{NO}}_2,-\mathrm{C}\equiv \mathrm{N},-{\mathrm{NH}}_2$ and $-{\mathrm{CH}}_2{\mathrm{NH}}_2$ in absolute configuration of an enantiomer is

How the electrons fill these orbitals depends on the strength of the ligand.
One electron fills each orbital before a second one joins in when these are surrounded by weak-field ligands.
The spins of these compounds are high.

The correct decreasing priority of ligands is,

${\mathrm{NO}}_2>{\mathrm{NH}}_2>\mathrm{C}\equiv \mathrm{N}>{\mathrm{CH}}_2{\mathrm{NH}}_2$