The correct geometry and hybridisation for ${\mathrm{XeF}}_4$ are

 The structure of ${\mathrm{XeF}}_4$ is as follows.

${\mathrm{XeF}}_4$ is ${\mathrm{AB}}_4{ \mathrm{L}}_2$ molecule in which the Xenon is bonded with four fluorine atoms with 4 sigma bonds and xenon has two lone pairs (4 sigma bonds and 2 lone pairs).

So, the hybridisation is ${\mathrm{sp}}^3{ \mathrm{d}}^2$.

And the shape or geometry stands out to be square planar since all fluorines are in same plane and have angle of 90 degree between them.