The correct geometry and hybridization for ${XeF}_{4}$ are

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$square planar, s p^{3} d^{2}$

$octahedral, s p^{3} d^{2}$

$trigonal bipyramidal, s p^{3} d$

$planar triangle, s p^{3} d^{3}$

answer is A.

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Detailed Solution

Geometry of the molecule is 3D-arrangement of electron pairs on central atom.
XeF₄ contains 4 bond pairs and 2 lone pairs electron around central atom Xe. The geometry of molecule is octahedral hybridisation. sp³d²shape of XeF₄ is square planar. All four bond pair electrons are directed towards four corners of square.

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