The correct increasing bond angle among ${\mathrm{BF}}_3, {\mathrm{PF}}_3 \mathrm{and} {\mathrm{ClF}}_3$ follow the order

In ${\mathrm{BF}}_3, \mathrm{B} \mathrm{is} {\mathrm{sp}}^2$ hybridized with bond angle ${120}^0\mathrm{C}. \mathrm{In} {\mathrm{PF}}_3, \mathrm{P} \mathrm{is} {\mathrm{sp}}^3$ hybridized but bond angle is less than ${109}^{0}28$ due to lone pair bond pair repulsion. In ${\mathrm{ClF}}_3, \mathrm{Cl} \mathrm{is} {\mathrm{sp}}^3\mathrm{d}$ hybridized having T-shape with bond angle ${90}^0\mathrm{C}.$