The correct increasing order of molecules in accordance with number of lone pair of electrons on the central-atom is :

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

${XeF}_{2} < H_{2} O < {NH}_{3}$

${NH}_{3} < H_{2} O < {XeF}_{2}$

${XeF}_{2} < {NH}_{3} > H_{2} O$

$H_{2} O = {XeF}_{2} = {NH}_{3}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The correct increasing order of molecules in accordance with number of lone pair of electrons on the central-atom is ${NH}_{3} < H_{2} O < {XeF}_{2}$

The number of lone pairs of electrons is found according to VSEPR theory. , The number of lone pairs of electrons on ${NH}_{3}, H_{2} O, {XeF}_{2}$ is 1, 2 and 3 respectively.

There are two bond pairs in xenon. Out of these eight, four are bond pairs, leaving Xenon with two lone pairs of electrons. Two of the electron pairs in the water molecule are lone pairs rather than bonded pairs. Three single bonds and one lone pair are present on the core nitrogen atom of the ammonia molecule.

Hence, the option C is correct.

Watch 3-min video & get full concept clarity