The correct increasing order of $\frac{e}{m}$ ratio (charge to m mass) of the given particles is : $\left(e=no. of e^{-}\right)$

The correct increasing order of $\frac{e}{m}$ ratio (charge to m mass) of the given particles is : ${\mathrm{Na}}^{+}<{{\mathrm{Mg}}^2}^{+} < {{\mathrm{Al}}^3}^{+}$

Electron charge to mass is expressed as the ratio e/m. Here, e denotes the particle's charge in coulombs and m denotes the cathode ray's mass in kilogram's.

$\frac{\mathrm{e}}{\mathrm{m}}\text{ ratio of }{\mathrm{Na}}^{+}\text{is }\frac{1}{11}=0.090$

$\frac{\text{ e }}{\mathrm{m}}\text{ ratio of }{\mathrm{Mg}}^{2+}\text{ is }\frac{2}{24}=0.083$

$\frac{\text{ e }}{\mathrm{m}}\text{ ratio of }{\mathrm{Al}}^{+3}\text{ is }\frac{3}{27}=0.11$

Hence, correct option is A.