The correct match is

	Molecule		Hybridisation
A)	XeF4	P)	sp3
B)	IF7	Q)	sp3d2
C)	${\mathrm{NH}}_4^{+}$	R)	sp3d3
D)	CO2	S)	SP

	(A)	(B)	(C)	(D)
1)	P	Q	R	S
2)	P	R	Q	S
3)	Q	R	P	S
4)	R	Q	P	S

$\mathrm{no}.\mathrm{of} \mathrm{hybrid} \mathrm{orbitals}(\mathrm{H}.\mathrm{O})=\frac{1}{2}\left(\mathrm{V}+\mathrm{M}-\mathrm{charge}\right)$

XeF₄ : no. of H.O=$\frac{1}{2}\left(8+4\right)=6\to {\mathrm{sp}}^3{\mathrm{d}}^2 \mathrm{hybridization}$

IF₇ : no. of H.O=$\frac{1}{2}\left(7+7\right)=7\to {\mathrm{sp}}^3{\mathrm{d}}^3 \mathrm{hybridization}$

${\mathrm{NH}}_4^{+}$:  no. of H.O= $\frac{1}{2}\left(5+4-1\right)=4\to {\mathrm{sp}}^3 \mathrm{hybridization}$

CO₂ :  no. of H.O= $\frac{1}{2}\left(4\right)=2\to \mathrm{sp} \mathrm{hybridization}$