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The correct order for acid strength of compounds $CH \equiv CH, {CH}_{3} - C \equiv CH and {CH}_{2} = {CH}_{2}$ is as follows

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${CH}_{3} - C \equiv CH > CH \equiv CH > {CH}_{2} = {CH}_{2}$

$HC \equiv CH > {CH}_{3} - C \equiv CH > {CH}_{2} = {CH}_{2}$

${CH}_{3} - C \equiv CH > {CH}_{2} = {CH}_{2} > CH \equiv CH$

$CH \equiv CH > {CH}_{2} = {CH}_{2} > {CH}_{3} - C \equiv CH$

answer is D.

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Detailed Solution

% S character increases acidic character increases

% S character SP > SP² > SP³

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