The correct order of basicities of the following compounds is:

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${CH}_{3} - {CH}_{2} - {NH}_{2}$

${({CH}_{3})}_{2} NH,$

answer is B.

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Detailed Solution

(1) > (3) > (2) > (4).

(1) More basic due to the presence of two LP $\bar{e}$ on each N.
(2) EtNH₂. Due to + I effect of (Et) group, but +I effect of two Me groups is greater than +I effect of (Et) group. Hence, (3)
is more basic than (2).
(3) (CH₃)₂NH. Due to (+I) effect of two Me groups.

(4)

(Amides are resonance stabilised; so they are the weakest bases. Amides behave as amphoteric.)

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