The correct order of boiling point is :

Higher BP equate to greater forces (because more thermal energy needed to separate the molecules in liquid state) AS, the size of the hydride molecules increases as you move down the Group, more energy is required.

Because oxygen is so much more electronegative than water, its molecules form H-bonds. Because of this, the intermolecular force creates practically a new (and higher) order, leading to the high BP in water.

Here, required order is,

${\mathrm{H}}_2\mathrm{O}>{\mathrm{H}}_2\mathrm{Te}>{\mathrm{H}}_2\mathrm{Se}>{\mathrm{H}}_2\mathrm{S}$ has the lowest boiling point.