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The correct order of bond angles is

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$H_{2} O < O F_{2} a n d N H_{3} < N F_{3}$

$O F_{2} < H_{2} O a n d N H_{3} > N F_{3}$

$N H_{3} > N F_{3} a n d P H_{3} > P F_{3}$

$O F_{2} < H O F a n d N H_{3} > N H_{4}^{+}$

answer is B.

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Detailed Solution

$O F_{2} < H_{2} O; N H_{3} > N F_{3}; N F_{3} < P F_{3}; O F_{2} > H O F; N H_{3} < N H_{4}^{+}$

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