The correct order of bond angles (largest first) in  ${\mathrm{H}}_2\mathrm{S}$,  ${\mathrm{NH}}_3$ , ${\mathrm{BF}}_3$ and ${\mathrm{SiH}}_4$is:

${\mathrm{BF}}_3$ has trigonal planar geometry with 3 bond pairs. The bond angle is $120°$.
${\mathrm{SiH}}_4$ is tetrahedral in shape with 4 bond pairs. The bond angle is $109.28°$.
${\mathrm{NH}}_3$ is pyramidal in shape with 3 bond pairs and one lone pair. The bond angle is $107.5°$
${\mathrm{H}}_2\mathrm{S}$ is bent shaped with 2 bond pairs and two lone pairs. The bond angle is $92.3°$.