The correct order of bond dissociation energy among ${\mathrm{N}}_2,{\mathrm{O}}_2,{\mathrm{O}}_2^{-}$  is shown in which of the following arrangements?

The molecular electroinc configuration along with their bond orders (BO) are as follows:

$\begin{array}{l}{\mathrm{N}}_2\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\mathrm{KK}\left(\sigma 2\mathrm{s}{)}^2\right(\sigma \ast 2\mathrm{s}{)}^2{\left(\pi 2{\mathrm{p}}_x\right)}^2{\left(\pi 2{\mathrm{p}}_y\right)}^2{\left(\sigma 2{\mathrm{p}}_z\right)}^2;\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\mathrm{BO}=3\\ {\mathrm{O}}_2\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\mathrm{KK}\left(\sigma 2\mathrm{s}{)}^2\right(\sigma \ast 2\mathrm{s}{)}^2{\left(\sigma 2{\mathrm{p}}_z\right)}^2{\left(\pi 2{\mathrm{p}}_x\right)}^2{\left(\pi 2{\mathrm{p}}_y\right)}^2{\left({\pi }^{\ast }2{\mathrm{p}}_x\right)}^1{\left({\pi }^{\ast }2{\mathrm{p}}_y\right)}^1;\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\mathrm{BO}=2\\ {\mathrm{O}}_2^{-}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\mathrm{KK}(\sigma 2\mathrm{s}{)}^2{\left({\sigma }^{\ast }2\mathrm{s}\right)}^2{\left(\sigma 2{\mathrm{p}}_z\right)}^2{\left(\pi 2{\mathrm{p}}_x\right)}^2{\left(\pi 2{\mathrm{p}}_y\right)}^2{\left({\pi }^{\ast }2{\mathrm{p}}_x\right)}^2{\left({\pi }^{\ast }2{\mathrm{p}}_y\right)}^1;\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\mathrm{BO}=1\frac{1}{2}\end{array}$The larger the bond order, larger the dissociation energy.