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Q.

The correct order of bond order values among the following is 
i) NO 
ii) NO+ 
iii) NO 
iv) NO+2 
v) NO–2

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a

ii < iii < iv < i < v

b

iv = ii < i < v < iii

c

i < iv < iii < ii < v

d

v < i < iv = iii < ii

answer is C.

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Detailed Solution

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NO-(16e-) : σ1s2σ*1s2σ2s2σ*2s2σ2px2π2py2π2pz2π*2py1π*2pz1 B.O=10-62=2

NO+(14e-) : σ1s2σ*1s2σ2s2σ*2s2π2py2π2pz2σ2px2 B.O=10-42=3

NO(15e-) : σ1s2σ*1s2σ2s2σ*2s2σ2px2π2py2π2pz2π*2py1π*2pz0 B.O=10-52=2.5

NO+2(13e-) : σ1s2σ*1s2σ2s2σ*2s2π2py2π2pz2σ2px1 B.O=9-42=2.5

NO-2(17e-) : σ1s2σ*1s2σ2s2σ*2s2σ2px2π2py2π2pz2π*2py2π*2pz1 B.O=10-72=1.5

Hence, the order of bond orders is, v < i < iv = iii < ii

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