The correct order of bond strength of $σ$ -bond is :

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$2 p - 2 p > 1 s - 2 p > 1 s - 1 s$

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$1 s - 1 s > 1 s - 2 p_{x} > 2 p_{x} - 2 p_{x}$

$2 p - 2 p = 1 s - 2 p = 1 s - 1 s$

answer is A.

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Detailed Solution

In chemistry, bond strength is the force that a chemical bond uses to hold two atoms together. Because of its proximity to the nucleus, the 1s-1s link is stronger than the 2p-2p bond.

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