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The correct order of decreasing second ionisation enthalpy of Ti(22), V(23), Cr and Mn(25) is

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V > Mn > Cr > Ti

Mn > Cr > Ti > V

Cr > Mn > V > Ti

Ti > V > Cr > Mn

answer is A.

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Detailed Solution

In general, IE₂ increases across a period. But due to stable d⁵ configuration, 'Cr⁺(4s⁰3d⁵)' has highest IE₂ value.

Hence, Cr > Mn > V > Ti

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