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Q.

The correct order of decreasing second ionization enthalpy 
Ti(22), V(23), Cr(24), Mn(25)

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a

V > Mn > Cr > Ti

b

Mn > Cr > Ti > V

c

Cr> Mn > V > Ti

d

Ti > V > Cr > Mn

answer is D.

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Detailed Solution

Cr+(3d5),Mn+(3d54s1),V+(3d34s1),Ti+(3d24s1)

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