The correct order of dipole moment of HF, HCl, HBr, Hl and $H_{2}$ Is :

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$H_{2} < HI < HBr < HF < HCl$

$H_{2} < HF < HCl < HBr < HI$

$H_{2} < HF < HBr < HCl < HI$

$H_{2} < HIl < HBr < HCl < HF$

answer is C.

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Detailed Solution

$HF > HCl > HBr > HI > H_{2}$ The electronegativity of the atoms in a chemical bond affects the dipole moment, which is a gauge of bond polarity. The dipole moment will be higher when the electronegativity of the atom is greater.

hence option is correct (c)

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