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The correct order of energy of the shells is ___________

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$K > L > M > N$

$L > K > M > N$

$N > K > L > M$

$N > M > L > K$

answer is D.

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Detailed Solution

K Shell is closer to the nucleus, so it has less energy, N shell is far away from the nucleus and has more energy so it has highest energy than K, L and M shells away from nucleus energy of orbit increases.

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