The correct order of hybridisation of the central atom in the following species:

${\mathrm{NH}}_3,{ \mathrm{XeO}}_2{\mathrm{F}}_2, {\mathrm{SeF}}_4,{ \mathrm{NO}}_2^{+}$

The hybridization of the central atom of ${\mathrm{NH}}_3,{ \mathrm{XeO}}_2{\mathrm{F}}_2, {\mathrm{SeF}}_4,{ \mathrm{NO}}_2^{+}$is $s{p}^3,s{p}^{3}d,s{p}^{3}d,sp$.

${\mathrm{sp}}^3$ type of hybridization is obtained when one nitrogen 2s orbital and three nitrogen 2p orbitals combine to generate four hybrid orbitals with equivalent energy, 

Hence, the option B is correct.