The correct order of hydration enthalpies of alkali metal ions is

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${Li}^{+} > {Na}^{+} > K^{+} > {Rb}^{+} > {Cs}^{+}$

${Li}^{+} > {Na}^{+} > K^{+} > {Cs}^{+} > {Rb}^{+}$

${Na}^{+} > {Li}^{+} > K^{+} > {Rb}^{+} > {Cs}^{+}$

${Na}^{+} > {Li}^{+} > K^{+} > {Cs}^{+} > {Rb}^{+}$

answer is D.

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Detailed Solution

Size : ${Li}^{+} > {Na}^{+} > K^{+} > {Rb}^{+} > {Cs}^{+}$

Lithium has the smallest ion hence, it will have the highest hydration enthalpy.
Caesium has the largest size hence, it will have minimum hydration energy.

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