The correct order of increasing C-O bond length of CO, ${CO}_{3}^{2 -}$ and CO₂

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${CO}_{3}^{2 -} < {CO}_{2} < CO$

$CO < {CO}_{3}^{2 -} < {CO}_{2}$

${CO}_{2} < CO < {CO}_{3}^{2 -}$

$CO < {CO}_{2} < {CO}_{3}^{2 -}$

answer is D.

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Detailed Solution

The higher the bond order, the shorter the C–O bond length will be. CO has a bond order of 3 (this is incorrect; it has a bond-order of at least 2.5). The carbonate anion has an average bond order of 1.33. Carbon dioxide has a bond order of 2.

Hence, the order of increasing C–O bond lengths is: $CO < {CO}_{2} < {CO}_{3}^{2 -}$

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