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The correct order of increasing radii of the ions Br^- ,F^- ,O^2- and S^2- is as follows

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${Br}^{-} < F^{-} < O^{2 -} < S^{2 -}$

$F^{-} < O^{2 -} < S^{2 -} < {Br}^{-}$

$F^{-} < {Br}^{-} < O^{2 -} < S^{2 -}$

$S^{2 -} < O^{2 -} < F^{-} < {Br}^{-}$

answer is C.

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Detailed Solution

F^- and O^2- are isoelectronic but nuclear charge of F^- > O². Hence, ionic radius of F^- < O^2-. So the order is F^-< O^2- < S^2- < Br^- .

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