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Q.

 The correct order of increasing s-character (in percentage) in the hybrid orbitals in below molecules /ions is (assume all hybrid orbitals are exactly equivalent) :

CO32I    XeF4II    I3III    NCl3IV   BeCl2V

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a

 II<IV<III<V< I 

b

II<III<IV<I<V

c

 III<II<I<V<IV 

d

II<IV<III<I<V

answer is A.

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Detailed Solution

Correct option is A

CO32sp2  XeF4sp3d2    I3sp3d    NCl3sp3    BeCl2sp

The correct order of increasing s−character (in percentage) in the hybrid orbitals of following molecules/ions is:

 (I) CO32       C  

undergoes sp2

 (II) XeF4      Xe 

undergoes sp3d2

 (III) I3           I 

undergoes  sp3d

 (IV) NCl3     N  

undergoes sp3

 (V) BeCl2     Be 

undergoes sp

S-character in hybrid orbitals increases as the number of p orbitals and d orbitals in the hybridization.

So the correct order of S-character in hybrid orbitals is sp>sp2>sp3>sp3d>sp3d2

So the correct option is II<III<IV<I<V

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