The correct order of magnetic moments (only spin value in BM) among is :

The compounds ${\left[{\mathrm{MnCl}}_4\right]}^{2-},{\left[{\mathrm{CoCl}}_4\right]}^{2-}\text{ and }{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}^{4-}$ have 5, 3, and o unpaired electrons, respectively. The magnetic moment values rise together with the number of unpaired electrons. Therefore, 

${\left[{\mathrm{MnCl}}_4\right]}^{2-}>{\left[{\mathrm{CoCl}}_4\right]}^{2-}>{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}^{4-}$is the right sequence of magnetic moments (spin values in BM).

$\mu =0\text{ for }{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}^{4-}$ 

Hence, the correct option is D.