The correct order of normal boiling points of O₂, $N_{2}, {NH}_{3} and {CH}_{4}$ for whom the values of van der Waals constant ' a ' are 1.360, 1.390, 4.170 and $2.253 L^{2} atm {mol}^{- 2}$ respectively is

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$O_{2} < N_{2} < {NH}_{3} < {CH}_{4}$

$O_{2} < N_{2} < {CH}_{4} < {NH}_{3}$

${NH}_{3} < {CH}_{4} < N_{2} < O_{2}$

${NH}_{3} < {CH}_{4} < O_{2} < N_{2}$

answer is B.

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Detailed Solution

The correct order of normal boiling points of O₂,N₂,NH₃ and CH₄ ( for whom the values of vander waals constant 'a' are 1.360, 1.390, 4.170 and 2.253 L² atm. mol⁻² respectively) is O₂<N₂<CH₄<NH₃.
Higher is the value of van der waals constant a, higher will be the boiling point as a is an indirect measure of the magnitude of attractive forces between the molecules.