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Q.

The correct order of number of unpaired electrons in the ion $C u^{2 +} N i^{2 +} F e^{3 +}$ and $C r^{3 +}$ is

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a

$F e^{3 +} > C r^{3 +} > C u^{2 +} > N i^{2 +}$

b

$F e^{2 +} > C r^{3 +} > N i^{2 +} > C u^{2 +}$

c

$C u^{2 +} > N i^{2 +} > C r^{3 +} > F e^{3 +}$

d

$N i^{2 +} > C u^{2 +} > F e^{3 +} > C r^{3 +}$

answer is C.

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Detailed Solution

As they have 5, 3, 2, 1 number of unpaired electrons respectively.

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