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Q.

The correct order of spin only magnetic mo-ment (in BM) for Mn2+, Cr2+ and Ti2+ ions is

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a

Mn2+ > Ti2+ > Cr2+

b

Mn2+ > Cr2+ > Ti2+

c

Cr2+ > Ti2+ > Mn2+

d

Ti2+ > Cr2+ > Mn2+

answer is C.

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Detailed Solution

 In  Mn(II)  five unpaired electrons are present. 3d5. Due to which it is highly magnetic in nature. To calculate magnetic moment we use the equation μ=√n (n+2), where n is the number of unpaired electrons. Greater the n value, greater will be the magnetic moment. In Cr+2 we have 4 and Ti+2 , 2 unpaired electrons.

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