The correct order of spin only magnetic mo-ment (in BM) for Mn²⁺, Cr²⁺ and Ti²⁺ions is

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Mn²⁺ > Ti²⁺ > Cr²⁺

Mn²⁺ > Cr²⁺ > Ti²⁺

Cr²⁺ > Ti²⁺ > Mn²⁺

Ti²⁺ > Cr²⁺ > Mn²⁺

answer is C.

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Detailed Solution

In Mn(II) five unpaired electrons are present. 3d5. Due to which it is highly magnetic in nature. To calculate magnetic moment we use the equation μ=√n (n+2), where n is the number of unpaired electrons. Greater the n value, greater will be the magnetic moment. In Cr+2 we have 4 and Ti+2 , 2 unpaired electrons.

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