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Q.

The correct order of the energy of molecular orbitals in a molecules having 4 electrons is

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a

$σ^{*} {}_{2 s}< π_{2 p} < σ_{2 pz}$

b

$σ_{2 s}^{*} < σ_{2 pz} = π_{2 px}$

c

$σ_{2 pz} < σ_{2 s} < π_{2 px}$

d

$σ_{2 s}^{*} > σ_{2 pz} > π_{2 px}$

answer is B.

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Detailed Solution

Molecules having 4 electrons

$σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < π 2 p_{x} = π 2 p_{y}) < σ 2 p_{z}$

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