The correct order of the oxidation states of nitrogen in $N O, N_{2} O$ , ${N O}_{2}$ and $N_{2} O_{3}$ is

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${N O}_{2} < N O < N_{2} O_{3} < N_{2} O$

$N_{2} O < N_{2} O_{3} < N O < {N O}_{2}$

$N_{2} O < N O < N_{2} O_{3} < {N O}_{2}$

${N O}_{2} < N_{2} O_{3} < N O < N_{2} O$

answer is C.

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Detailed Solution

Oxidation state of N in NO = +2

Oxidation state of N in $N_{2} O$ =+1

Oxidation state of N in ${N O}_{2}$ = +4

Oxidation state of N in $N_{2} O_{3}$ = +3

The correct order of the oxidation states of nitrogen is $N_{2} O < N O < N_{2} O_{3} < {N O}_{2} .$

Therefore, option C is correct.

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