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The correct order of the stoichiometries of $A g C l$ formed when $A g N O_{3}$ in excess is treated with the complexes $C o C l_{3} 4 N H_{3}$ & $C o C l_{3} 5 N H_{3}$ respectively is

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two $A g C l$ and one $A g C l$

one $A g C l$ and two $A g C l$

Three $A g c l$ and two $A g c l$

Two $A g c l$ and Three $A g c l$

answer is B.

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Detailed Solution

$C O C l_{3} 4 N H_{3} \to {[C O {(N H_{3})}_{4} C l_{2}]}^{+} + C l^{-}$
$A g^{+} + C l^{-} \to A g C l$
$C O C l_{3} 5 N H_{3} \to {[C O {(N H_{3})}_{5} C l]}^{+ 2} + 2 C l^{-}$
$2 A g^{+} + 2 C l^{-} \to 2 A g C l$

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