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The correct order of $∆_{0}$ value of the give complexes is :
$(I) [Co {(H_{2} O)}_{6}]^{3 +}$ $(II) {[{CoF}_{6}]}^{3 -}$ $(III) [Co {({NH}_{3})}_{6}]^{3 +}$ $(IV) [Co {(CN)}_{6}]^{3 -}$

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$III < II < I < IV$

$II < I < IV < III$

$I < II < III < IV$

$II < I < III < IV$

answer is C.

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Detailed Solution

$\overset{F ¯ H_{2} O {NH}_{3} CN ¯}{\to}$

$\to$ Intensity of ligands increases (electron donating ability)

$\to ∆_{0} (CSFE)$ increases

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