The correct order of pKa∘ of given acids is

p K a ∘ ( RCOOH ) < p K a ∘ H 2 CO 3 > p K a ∘ ( PhOH )

p K a ∘ ( RCOOH ) < p K a ∘ H 2 CO 3 > p K a ∘ ( PhOH )

p K a ∘ ( RCOOH ) > p K a ∘ H 2 CO 3 < p K a ∘ ( PhOH )

p K a ∘ ( RCOOH ) > p K a ∘ H 2 CO 3 > p K a ∘ ( PhOH )

p K a ∘ ( RCOOH ) < p K a ∘ H 2 CO 3 < p K a ∘ ( PhOH )

p K a ∘ ( RCOOH ) < p K a ∘ H 2 CO 3 > p K a ∘ ( PhOH )

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The correct order of $p K_{a}^{\circ}$ of given acids is

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$p K_{a}^{\circ} (RCOOH) > p K_{a}^{\circ} (H_{2} {CO}_{3}) < p K_{a}^{\circ} (PhOH)$

$p K_{a}^{\circ} (RCOOH) > p K_{a}^{\circ} (H_{2} {CO}_{3}) > p K_{a}^{\circ} (PhOH)$

$p K_{a}^{\circ} (RCOOH) < p K_{a}^{\circ} (H_{2} {CO}_{3}) < p K_{a}^{\circ} (PhOH)$

$p K_{a}^{\circ} (RCOOH) < p K_{a}^{\circ} (H_{2} {CO}_{3}) > p K_{a}^{\circ} (PhOH)$

answer is D.

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The correct order of $p K_{a}^{\circ}$ of given acids is $p K_{a}^{\circ} (RCOOH) < p K_{a}^{\circ} (H_{2} {CO}_{3}) < p K_{a}^{\circ} (PhOH)$

Since $K_{a} (RCOOH) > K_{a} (H_{2} {CO}_{3}) > K_{a} (PhOH), p K_{a}^{\circ}$ values follow reverse order.

Hence, option D is correct.

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