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The correct sequence which shows decreasing order of the ionic radii of the elements is

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Al³⁺ > Mg²⁺ > Na⁺ > F^– > O^2–

Na⁺ > F^– > Mg²⁺ > O^2– > Al³⁺

O^2– > F^– > Na⁺ > Mg²⁺ > Al³⁺

Na⁺ > Mg²⁺ > Al³⁺ > O^2– > F^–

answer is C.

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Detailed Solution

In case of isoelectronic species, Ionic radius increases as -ve charge(no. of electrons) increases and +ve charge(nuclear charge) decreases.

Hence, O^2– > F^– > Na⁺ > Mg²⁺ > Al³⁺

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