The correct set(s) of order is/ are:

1) The covalent character increases as the cation size decreases.
As a result, covalent character rises from  .
2) Since, lattice energy is inversely proportional to solubility. So,  
3)Three bond pairs and one lone pair is used for the pyramidal structure of ${\mathrm{NH}}_3$. A bond angle of  exists.
Trigonal planar shape and three bond pairs characterise ${\mathrm{BF}}_3$. So, Bond angles measure  .
4) In $\mathrm{sp}, {\mathrm{sp}}^2$and ${\mathrm{sp}}^3$ hybridised carbon, the proportion of the s character is 50%, 33.33%, and 25%, respectively.
${\mathrm{XeF}}_4\left({90}^{\circ }\right)<{\mathrm{H}}_2\mathrm{O}\left({104.5}^{\circ }\right)<{\mathrm{NH}}_3\left({107}^{\circ }\right)<{\mathrm{BF}}_3\left({120}^{\circ }\right).$

The correct option is A,B,C,D.