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The correct stability order of the following resonance structure is
$I) H_{2} C = \overset{+}{N} = \bar{N} I I) H_{2} \overset{+}{C} - \overset{}{N} = \bar{N} I I I) H_{2} \bar{C} - \overset{+}{N} \equiv \overset{}{N} I V) H_{2} \bar{C} - \overset{}{N} = \overset{+}{N}$

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$I > I I > I V > I I I$

$I > I I I > I I > I V$

$I I > I > I I I > I V$

$I I I > I > I V > I I$

answer is B.

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Detailed Solution

$I) H_{2} C = \overset{+}{N} = \bar{N} I I) H_{2} \overset{+}{C} - \overset{}{N} = \bar{N} I I I) H_{2} \bar{C} - \overset{+}{N} \equiv \overset{}{N} I V) H_{2} \bar{C} - \overset{}{N} = \overset{+}{N}$

I is more stable due to negative charge on nitrogen

I and III has more stability due to less charge separation.

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