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The correct statement among the following is

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The first ionization potential of Al is less than the first ionization potential of Mg

The second ionization potential of Mg is greater than the second ionization potential of Na

The first ionization potential of Na is less than the first ionization potential of Mg

The third ionization potential of Mg is greater than the third ionization potential of Al

answer is B.

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Detailed Solution

$I E_{2}$ of Mg is lower than that of Na because in case of $M g^{+}$ , 3s-electron has to be removed where as in case of $N a^{+},$ an electron is removed from the stable inert gas configuration which is difficult

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