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${BeCl}_{2}$ is a covalent compound

${BeCl}_{2}$ is an electron deficient molecule

${BeCl}_{2}$ can form dimer

The hybrid state of $Be$ in ${BeCl}_{2}$ is ${sp}^{2}$

answer is A.

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Detailed Solution

a) Since of $Be$ tiny size and high charge density, its polarising strength is at its peak because ${Be}^{+ 2}$ ion literally pulls the electron cloud from ${Cl}^{-}$ , effectively dividing the electron pair. This gives ${BeCl}_{2}$ a covalent nature.

b) The outer shell of the beryllium atom has four electrons, which is not the electron configuration of a noble gas. In this case, the octet rule is not satisfied. Thus, it lacks electrons.

C) Dimers of ${BeCl}_{2}$ form.

D) $sp$ , not ${sp}^{2}$ , is the hybrid state of $Be$ in ${BeCl}_{2}$ .

Options A, B, and C are therefore correct.

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